Thursday 24 April 2014

Readers’ Comments

204Tuesday, 14 May 2013 10:19
I really enjoyed the puzzles, behind most of which I recognize Vitaly's work about MCR and waits analysis he studied years ago.

It is difficult to judge the difficulty of problems, but some did take me some time to solve.

I especially enjoyed the '32nd of December' and its fourth question.

Thanks to Vitaly for the problems, to Martin for hosting the "venue" and congrats to Sylvain and Scott for their success.
203Wednesday, 08 May 2013 12:32
Sylvain Malbec
Q: "each player melded exactly 12 one-suit tiles"
A: two kongs of the same suit (i.e. 8 one-suit tiles) and a kong of wind

So... winds are now suit tiles?
And they are in every suit?
Looks like I've misunderstood the question and it was actually an easy one!
202Monday, 06 May 2013 00:15
Scott D. Miller
I really enjoyed the puzzles, which no doubt improved my mahjong game considerably. They forced me to consider wait situations and patterns which I hadn't given much though to before. Congratulations to Sylvain Malbec! And a great thanks to Vitaly Novikov for conceiving the puzzles, and to Martin Rep and Mahjong News for providing the venue.
201Thursday, 25 April 2013 07:07
Scott Miller
I'm not clear on why the time limit was extended an additional three days.

Was it because I was the only one to answer the question within the allotted time?

Just curious.

200Wednesday, 24 April 2013 02:08
Sylvain Malbec
Fourth deal
At first, it looks like each player had three pure melded kongs, two of them separated by two numbers (e.g. 1 and 4), and that their left-side neighbour is waiting for these two said kongs with a ryanmen (e.g. _23_).
But it turns out there are not enough tiles for that.

So, here's the trick:
Watson had: melded: 1111m 4444m 5555m, concealed: 23s EE.
Lestrade had: melded: 1111s 4444s 5555s, concealed: 23p SS.
Holmes had: melded: 1111p 4444p 5555p, concealed: 78m WW.
Mrs. Hudson had: melded: 6666m 9999m, concealed: RRRR(concealed kong) 23m NN, and erronously melded as flowers: 2223m.

It certainly "cut off all conceivable scenarios".

‘Full House’: the Solution

altDr. Watson had asked Sherlock Holmes how a hand with as many fans as possible can be constructed. Sherlock answered that he could solve that problem in less time it would take him than smoking half a pipe. Could you - even if you never smoke? Here’s the answer…

Question: Please, construct a hand containing as maximum of different fans.
Answer. Omitting reasoning here is a hand:

Concealed -- altaltaltalt, altaltaltalt, altaltaltaltaltaltalt, after replacing Kong alt comes (last tile from the wall and last tile of a kind):
1. 2= Prevalent Wind
2. 2 = Seat Wind
3. 2*1 = Pung of Terminals or Honors (two occurrences)
4. 16 = Three Concealed Pungs
5. 2 = Double Pung
6. 8 = Two Concealed Kongs
7. 4 = Outside Hand
8. 2 = Tile Hog
9. 1 = One Voided Suit
10. 1 = Closed Wait
11. 4 = Fully Concealed Hand
12. 8 = Out with Replacement Tile
13. 8 = Last Tile Draw
14. 4 = Last Tile
15. 8*1 = Flowers (8 ocurrences, not shown)
Totalling 72 pts on 15 different fans (altogether 23 fans).

Mahjong News | Copyright © 1997-2014 | About Us | Sitemap | Contact